In an electrical system, an open circuit most accurately results in which condition?

In an electrical system, an open circuit most accurately results in which condition?

• A. No current flow
• B. Excessive current
• C. Normal operation
• D. Short duration interference

Answer: (A)

An open circuit means the conducting path is broken, so there is no complete loop for current to flow. With a voltage source present but no closed path, the current is effectively zero because the resistance is infinite (I = V/R). You can have the source voltage appear on the open side, but no energy is delivered to a load. This is different from a short circuit, where a very low-resistance path causes a large, potentially damaging current, and from normal operation, which requires a closed circuit for current to flow. A brief disturbance isn’t the defining condition of an open circuit; the hallmark is the break in the path that stops current entirely.

An open circuit means the conducting path is broken, so there is no complete loop for current to flow. With a voltage source present but no closed path, the current is effectively zero because the resistance is infinite (I = V/R). You can have the source voltage appear on the open side, but no energy is delivered to a load. This is different from a short circuit, where a very low-resistance path causes a large, potentially damaging current, and from normal operation, which requires a closed circuit for current to flow. A brief disturbance isn’t the defining condition of an open circuit; the hallmark is the break in the path that stops current entirely.